最新消息: USBMI致力于为网友们分享Windows、安卓、IOS等主流手机系统相关的资讯以及评测、同时提供相关教程、应用、软件下载等服务。

技术经济学(5-7单元课后题答案)

IT圈 admin 33浏览 0评论

2024年5月21日发(作者:革云霞)

第五章:

10

解: 600(P/A,10%,10) = 600 × 6.144 = 3686.4

11

F = 500(1+8%)×(F/A,8%,8) = 500 × 1.08 × 10.637 = 5744

12

解: 1200(1+12%)= 250(P/A,12%,n)

n = 9.14 n’ = 9.14+1=10.14

13

16%

12

i(1)117.23%

> 17%

12

14

解:5000(F/A,6%,35)= A(P/A,6%,15)

A = 57366.7

15

2000(1+12%)+1500 = A(P/A,12%,5)

A = 1037.5

16

5600

P46666.7

12%

第六章:

10题:

T3

50804060

60

3.5

NPV = -50–80 (P/F,10%,1) + 40(P/F,10%,2) + 60(P/A,10%,4) (P/F,10%,2)

= 67.51

NAV = 67.51(A/P,10%,6) = 15.5

i

1

= 25% NPV

1

= 2.3; i

2

= 30% NPV

2

= -10.97

1

年份

NCF

2.3

IRR25%(30%25%)25.87%

2.310.97

67.51

NPVR0.55

80

50

1.1

0

-50

-50

-50

1

-80

-72.72

-122.73

2

40

33.06

-89.67

3

60

45.08

-44.59

4

60

40.98

-3.61

5

60

37.25

33.64

6

60

33.87

67.5

NCF× (P/F,10%,t)

∑NCF× (P/F,10%,t)

11

T

d

4

3.61

37.25

4.1

NPV = - 1000 – 2000 ( P/F,12%,1 ) – 1500 ( P/F,12%,2 )

+ 1450 ( P/A,12%,8 ) ( P/F,12%,2 ) = 1761

12

解(1) 80000 = 12600 ( P/A, IRR, 8 )

( P/A, IRR, 8 ) = 6.349

i1 = 5% NPV1 = -80000 + 12600 × 6.436 = 1434

i2 = 6% NPV2 = -80000 +12600 × 6.210 = - 1754

2

IRR5%

1434

1%5.45%

14341754

2024年5月21日发(作者:革云霞)

第五章:

10

解: 600(P/A,10%,10) = 600 × 6.144 = 3686.4

11

F = 500(1+8%)×(F/A,8%,8) = 500 × 1.08 × 10.637 = 5744

12

解: 1200(1+12%)= 250(P/A,12%,n)

n = 9.14 n’ = 9.14+1=10.14

13

16%

12

i(1)117.23%

> 17%

12

14

解:5000(F/A,6%,35)= A(P/A,6%,15)

A = 57366.7

15

2000(1+12%)+1500 = A(P/A,12%,5)

A = 1037.5

16

5600

P46666.7

12%

第六章:

10题:

T3

50804060

60

3.5

NPV = -50–80 (P/F,10%,1) + 40(P/F,10%,2) + 60(P/A,10%,4) (P/F,10%,2)

= 67.51

NAV = 67.51(A/P,10%,6) = 15.5

i

1

= 25% NPV

1

= 2.3; i

2

= 30% NPV

2

= -10.97

1

年份

NCF

2.3

IRR25%(30%25%)25.87%

2.310.97

67.51

NPVR0.55

80

50

1.1

0

-50

-50

-50

1

-80

-72.72

-122.73

2

40

33.06

-89.67

3

60

45.08

-44.59

4

60

40.98

-3.61

5

60

37.25

33.64

6

60

33.87

67.5

NCF× (P/F,10%,t)

∑NCF× (P/F,10%,t)

11

T

d

4

3.61

37.25

4.1

NPV = - 1000 – 2000 ( P/F,12%,1 ) – 1500 ( P/F,12%,2 )

+ 1450 ( P/A,12%,8 ) ( P/F,12%,2 ) = 1761

12

解(1) 80000 = 12600 ( P/A, IRR, 8 )

( P/A, IRR, 8 ) = 6.349

i1 = 5% NPV1 = -80000 + 12600 × 6.436 = 1434

i2 = 6% NPV2 = -80000 +12600 × 6.210 = - 1754

2

IRR5%

1434

1%5.45%

14341754

发布评论

评论列表 (0)

  1. 暂无评论